Min Number

TimeLimit:1000MS  MemoryLimit:32MB
64-bit integer IO format:%I64d
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Problem Description

Now you are given one non-negative integer n in 10-base notation, it will only contain digits ('0'-'9'). You are allowed to choose 2 integers i and j, such that: i!=j, 1≤i<j≤|n|, here |n| means the length of n’s 10-base notation. Then we can swap n[i] and n[j].

For example, n=9012, we choose i=1, j=3, then we swap n[1] and n[3], then we get 1092, which is smaller than the original n.

Now you are allowed to operate at most M times, so what is the smallest number you can get after the operation(s)?

Please note that in this problem, leading zero is not allowed!

Input

The first line of the input contains an integer T (T≤100), indicating the number of test cases.

Then T cases, for any case, only 2 integers n and M (0≤n<10^1000, 0≤M≤100) in a single line.

Output
For each test case, output the minimum number we can get after no more than M operations.
SampleInput
3
9012 0
9012 1
9012 2
SampleOutput
9012
1092
1029
Submit
题目统计信息详细
总AC数25
通过人数25
尝试人数25
总提交量48
AC率52.08%
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