Max Sum Plus Plus

TimeLimit: 2000/1000 MS (Java/Others)  MemoryLimit: 65536/32768 K (Java/Others)
64-bit integer IO format:%I64d
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Problem Description
Now I think you have got an AC in Ignatius.L's "Max Sum" problem. To be a brave ACMer, we always challenge ourselves to more difficult problems. Now you are faced with a more difficult problem.

Given a consecutive number sequence S 1, S 2, S 3, S 4 ... S x, ... S n (1 ≤ x ≤ n ≤ 1,000,000, -32768 ≤ S x ≤ 32767). We define a function sum(i, j) = S i + ... + S j (1 ≤ i ≤ j ≤ n).

Now given an integer m (m > 0), your task is to find m pairs of i and j which make sum(i 1, j 1) + sum(i 2, j 2) + sum(i 3, j 3) + ... + sum(i m, j m) maximal (i x ≤ i y ≤ j x or i x ≤ j y ≤ j x is not allowed).

But I`m lazy, I don't want to write a special-judge module, so you don't have to output m pairs of i and j, just output the maximal summation of sum(i x, j x)(1 ≤ x ≤ m) instead. ^_^
Input
Each test case will begin with two integers m and n, followed by n integers S 1, S 2, S 3 ... S n.
Process to the end of file.
Output
Output the maximal summation described above in one line.
SampleInput
1 3 1 2 3
2 6 -1 4 -2 3 -2 3
SampleOutput
6
8

 
Hint
Huge input, scanf and dynamic programming is recommended.
Submit
题目统计信息详细
总AC数79
通过人数52
尝试人数58
总提交量138
AC率37.68%
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