DNA sequence

TimeLimit: 15000/5000 MS (Java/Others)  MemoryLimit: 32768/32768 K (Java/Others)
64-bit integer IO format:%I64d
未提交 | 登录后收藏 | 已有5人收藏了本题
Problem Description
The twenty-first century is a biology-technology developing century. We know that a gene is made of DNA. The nucleotide bases from which DNA is built are A(adenine), C(cytosine), G(guanine), and T(thymine). Finding the longest common subsequence between DNA/Protein sequences is one of the basic problems in modern computational molecular biology. But this problem is a little different. Given several DNA sequences, you are asked to make a shortest sequence from them so that each of the given sequence is the subsequence of it.

For example, given "ACGT","ATGC","CGTT" and "CAGT", you can make a sequence in the following way. It is the shortest but may be not the only one.

Input
The first line is the test case number t. Then t test cases follow. In each case, the first line is an integer n ( 1<=n<=8 ) represents number of the DNA sequences. The following k lines contain the k sequences, one per line. Assuming that the length of any sequence is between 1 and 5.
Output
For each test case, print a line containing the length of the shortest sequence that can be made from these sequences.
SampleInput
1
4
ACGT
ATGC
CGTT
CAGT
SampleOutput
8
Submit
题目统计信息详细
总AC数31
通过人数25
尝试人数27
总提交量51
AC率49.02%
AC该题后可以添加标签
贴完标签可以获得20ACB。
并且可以获得本题所有提交代码查看权限。
点击标题可以显示标签。
如果你还没认真思考过这题,请不要查看标签
如果您已经通过了该题,请务为该题贴上标签

T^T Online Judge

[BUG反馈] [FAQ] [闽ICP备17026590号-1]
当前版本:3.24 系统时间: